This collection features ten resources on the topic of area.

The resources feature:

  • Concept development lessons that focus on developing conceptual understanding of significant mathematical ideas.
  • Problem solving lessons that focus on the application of previously learned mathematics to non-routine unstructured problems.
  • Tasks that provide mathematically rich problems that come with work for students to peer assess.

The Mathematics Assessment Resource Service (MARS) is a collaboration between the University of California at Berkeley and the Shell Centre team at the University of Nottingham, with support from the Bill and Melinda Gates Foundation. The team is known around the world for its innovative work in maths education.

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Temple geometry

This task is designed to assess how well students understand applying Pythagoras’ theorem in an unfamiliar situation and calculating areas of circles.

During the Edo period (1603-1897) of Japanese history, geometrical puzzles were hung in the holy temples as offerings to the gods and as challenges to...

Calculating arcs and areas of sectors in circles

This lesson develops the concept of finding areas of sectors. In particular students will:

  • Find perimeters, areas, and arc lengths of sectors using formulas
  • Find the relationships between arc lengths, and areas of sectors after scaling
  • Using radians

The initial challenge...

Evaluating statements about enlargements

This lesson develops the concepts of:

  • Finding perimeters, areas, and volumes using formulas.
  • Finding relationships between perimeters, areas, and volumes of shapes after scaling.

There are three initial questions to consider that deal with:

  • The perimeter of a circle...

Evaluating statements about length and area

This lesson develops the concepts of length and area. Particular attention is given to proving why two areas are or are not equal.

The lesson begins with three questions regarding area that students must classify as ‘sometimes, always, or never true’. An example is ‘if you join the midpoints of the opposite...

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